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Subnetting a 64 from a 48
![[us]](/s/countries/us.gif) Shadow Hawkins on Saturday, 31 May 2008 20:22:22
If I recall correctly a /48 subnet is actually bigger than a /64 one. If I am not correct then please correct me on this. Anyways my issue is that my router will refuse to broadcast a /48 subnet. It will only do a /64 one. For now this seems to work fine however I am worried that I am alloting more than I actually have.
In contract can someone tell me how big a 64 subnet and a 48 subnet actually is?
Subnetting a 64 from a 48
A /48 contains 65536 /64's. See Wiki: Subnet for details.
Anyways my issue is that my router will refuse to broadcast a /48 subnet.
You do realize that a /64 is already 2^64 IP addresses. A /48 on a single ethernet would be quite insane.
For now this seems to work fine however I am worried that I am alloting more than I actually have.
Nope, as the /48 indicates that from the 128-bits of IPv6 address, 48 bits are for the network, while (128-48 = 80) bits are for the host. Which is why one uses 64 bits on the network, thus leaving 64 bits for the host.
In contract can someone tell me how big a 64 subnet and a 48 subnet actually is?
/64 = 2^(128-64) = large number
/48 = 2^(128-48) = an even large number
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![[ch]](/s/countries/ch.gif)
on Saturday, 31 May 2008 20:30:59
Posting is only allowed when you are